What are the solutions to the equation 18r^2+6r=0 ?

The solutions to the equation 18r^2+6r=0 are r=0,r=-1/3

Find the zeros of 18r^2+6r=0

The zeros of 18r^2+6r=0 are r=0,r=-1/3

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18 r^{2} + 6 r = 0

r = 0, r = - \frac{1}{3}

Solution steps

18 r^{2} + 6 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 18 \cdot 0}{2 \cdot 18}

6^{2} - 4 \cdot 18 \cdot 0 = 6

r_{1, 2} = \frac{- 6 \pm 6}{2 \cdot 18}

Separate the solutions

r_{1} = \frac{- 6 + 6}{2 \cdot 18}, r_{2} = \frac{- 6 - 6}{2 \cdot 18}

r = \frac{- 6 + 6}{2 \cdot 18} : 0

r = \frac{- 6 - 6}{2 \cdot 18} : - \frac{1}{3}

The solutions to the quadratic equation are:

r = 0, r = - \frac{1}{3}

f = - 2 + 6

0 = X^{2} + 7 X + 12

12 x^{2} - 40 x - 63 = 0

3 x + 5 = 1

(\frac{3}{5})^{4}

What are the solutions to the equation 18r^2+6r=0 ?
The solutions to the equation 18r^2+6r=0 are r=0,r=-1/3
Find the zeros of 18r^2+6r=0
The zeros of 18r^2+6r=0 are r=0,r=-1/3