What is the answer to b(x-2)/(3x+4)=-3 ?

The answer to b(x-2)/(3x+4)=-3 is x=(-12+2b)/(b+9);\quad b\ne-9

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b(x-2)/(3x+4)=-3

b \frac{x - 2}{3 x + 4} = - 3

x = \frac{- 12 + 2 b}{b + 9}; b \neq = - 9

Solution steps

b \frac{x - 2}{3 x + 4} = - 3

Simplify

b \frac{x - 2}{3 x + 4} : \frac{b ( x - 2 )}{3 x + 4}

\frac{b ( x - 2 )}{3 x + 4} = - 3

Multiply both sides by

3 x + 4

b (x - 2) = - 3 (3 x + 4)

Expand

b (x - 2) : b x - 2 b

Expand

- 3 (3 x + 4) : - 9 x - 12

b x - 2 b = - 9 x - 12

Move

2 b

to the right side

b x = - 9 x - 12 + 2 b

Move

9 x

to the left side

b x + 9 x = - 12 + 2 b

Factor

b x + 9 x : x (b + 9)

x (b + 9) = - 12 + 2 b

Divide both sides by

b + 9; b \neq = - 9

x = \frac{- 12 + 2 b}{b + 9}; b \neq = - 9

2 x - 2 + \frac{3}{x + 2} = 0

\frac{3 x + 7}{x + 2} + x = 3

ab = \frac{m}{x + 1}

0 = \frac{5}{x ^{2} + 1}

\frac{1}{2 x + 13 - 1.5 x} = 3 x + 6 - 9

What is the answer to b(x-2)/(3x+4)=-3 ?
The answer to b(x-2)/(3x+4)=-3 is x=(-12+2b)/(b+9);\quad b\ne-9