What is the answer to 4x^{-4}-7x^{-2}-36=0 ?

The answer to 4x^{-4}-7x^{-2}-36=0 is x= 2/3 i,x=-2/3 i,x= 1/2 ,x=-1/2

Solve for x: 4x^{-4}-7x^{-2}-36=0

The solution is x= 2/3 i,x=-2/3 i,x= 1/2 ,x=-1/2

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4 x^{- 4} - 7 x^{- 2} - 36 = 0

x = \frac{2}{3} i, x = - \frac{2}{3} i, x = \frac{1}{2}, x = - \frac{1}{2}

Solution steps

4 x^{- 4} - 7 x^{- 2} - 36 = 0

Refine

\frac{4}{x ^{4}} - \frac{7}{x ^{2}} - 36 = 0

Multiply by LCM

4 - 7 x^{2} - 36 x^{4} = 0

Solve

4 - 7 x^{2} - 36 x^{4} = 0 : x = \frac{2}{3} i, x = - \frac{2}{3} i, x = \frac{1}{2}, x = - \frac{1}{2}

x = \frac{2}{3} i, x = - \frac{2}{3} i, x = \frac{1}{2}, x = - \frac{1}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0

Combine undefined points with solutions:

x = \frac{2}{3} i, x = - \frac{2}{3} i, x = \frac{1}{2}, x = - \frac{1}{2}

\frac{2}{x + 2} + 2 = \frac{12}{x + 2}

3 + \frac{1}{x} = \frac{x}{7}

\frac{1}{2 x + 3} = (2 x + 3)^{- 1}

\frac{1}{x ^{2}} = 10

6 = \frac{3}{2 x - 2.5}

What is the answer to 4x^{-4}-7x^{-2}-36=0 ?
The answer to 4x^{-4}-7x^{-2}-36=0 is x= 2/3 i,x=-2/3 i,x= 1/2 ,x=-1/2
Solve for x: 4x^{-4}-7x^{-2}-36=0
The solution is x= 2/3 i,x=-2/3 i,x= 1/2 ,x=-1/2