What is (2x+3)/3 >(6x+2)/9 ?

The solution to (2x+3)/3 >(6x+2)/9 is True for all x

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(2x+3)/3 >(6x+2)/9

\frac{2 x + 3}{3} > \frac{6 x + 2}{9}

True for all x

Interval Notation

(- \infty, \infty)

Solution steps

\frac{2 x + 3}{3} > \frac{6 x + 2}{9}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(2 x + 3) \cdot 9 > 3 (6 x + 2)

Expand

(2 x + 3) \cdot 9 : 18 x + 27

Expand

3 (6 x + 2) : 18 x + 6

18 x + 27 > 18 x + 6

Move

27

to the right side

18 x > 18 x - 21

Move

18 x

to the left side

0 > - 21

Therefore, the solution is

True for all x

x^{4} + x

(2 m + 2)^{2} + (3 m)^{2} = (5 m)^{2}

x^{2} + 16 x - 145 = 10 x - 7

3.4 = - 13.6 + (- 3.4 c) + 1.7 c

x^{2} + 21 < 10 x

What is (2x+3)/3 >(6x+2)/9 ?
The solution to (2x+3)/3 >(6x+2)/9 is True for all x