What is the answer to 1+2x^{-1}+2x^{-2}=0 ?

The answer to 1+2x^{-1}+2x^{-2}=0 is x=-1+i,x=-1-i

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1+2x^{-1}+2x^{-2}=0

1 + 2 x^{- 1} + 2 x^{- 2} = 0

x = - 1 + i, x = - 1 - i

Solution steps

1 + 2 x^{- 1} + 2 x^{- 2} = 0

Refine

1 + \frac{2}{x} + \frac{2}{x ^{2}} = 0

Multiply by LCM

x^{2} + 2 x + 2 = 0

Solve

x^{2} + 2 x + 2 = 0 : x = - 1 + i, x = - 1 - i

x = - 1 + i, x = - 1 - i

x = \frac{x ^{3} + 3 x - 1}{x ^{2}}

8 = \frac{- 18 + ( 3 )}{( 8 ) ( 16 - 40 n )}

x - x^{- 1} = 2

x^{- 2} = 0.01

4 = \frac{1}{3 r - 6}

What is the answer to 1+2x^{-1}+2x^{-2}=0 ?
The answer to 1+2x^{-1}+2x^{-2}=0 is x=-1+i,x=-1-i
Solve for x: 1+2x^{-1}+2x^{-2}=0
The solution is x=-1+i,x=-1-i