What are the solutions to the equation 3x^2+10x-12=0 ?

The solutions to the equation 3x^2+10x-12=0 are x=(-5+sqrt(61))/3 ,x=-(5+sqrt(61))/3

Find the zeros of 3x^2+10x-12=0

The zeros of 3x^2+10x-12=0 are x=(-5+sqrt(61))/3 ,x=-(5+sqrt(61))/3

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3 x^{2} + 10 x - 12 = 0

x = \frac{- 5 + 61}{3}, x = - \frac{5 + 61}{3}

Solution steps

3 x^{2} + 10 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 12) = 261

x_{1, 2} = \frac{- 10 \pm 2 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 2 61}{2 \cdot 3}, x_{2} = \frac{- 10 - 2 61}{2 \cdot 3}

x = \frac{- 10 + 2 61}{2 \cdot 3} : \frac{- 5 + 61}{3}

x = \frac{- 10 - 2 61}{2 \cdot 3} : - \frac{5 + 61}{3}

The solutions to the quadratic equation are:

x = \frac{- 5 + 61}{3}, x = - \frac{5 + 61}{3}

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What are the solutions to the equation 3x^2+10x-12=0 ?
The solutions to the equation 3x^2+10x-12=0 are x=(-5+sqrt(61))/3 ,x=-(5+sqrt(61))/3
Find the zeros of 3x^2+10x-12=0
The zeros of 3x^2+10x-12=0 are x=(-5+sqrt(61))/3 ,x=-(5+sqrt(61))/3