What are the solutions to the equation -x^2+9x=x^2-5x ?

The solutions to the equation -x^2+9x=x^2-5x are x=0,x=7

Find the zeros of -x^2+9x=x^2-5x

The zeros of -x^2+9x=x^2-5x are x=0,x=7

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- x^{2} + 9 x = x^{2} - 5 x

x = 0, x = 7

Solution steps

- x^{2} + 9 x = x^{2} - 5 x

Move

5 x

to the left side

- x^{2} + 14 x = x^{2}

Move

x^{2}

to the left side

- 2 x^{2} + 14 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1 4^{2} - 4 (- 2) \cdot 0 = 14

x_{1, 2} = \frac{- 14 \pm 14}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 14 + 14}{2 ( - 2 )}, x_{2} = \frac{- 14 - 14}{2 ( - 2 )}

x = \frac{- 14 + 14}{2 ( - 2 )} : 0

x = \frac{- 14 - 14}{2 ( - 2 )} : 7

The solutions to the quadratic equation are:

x = 0, x = 7

m z - 5 m h^{2} - 5 n z + 25 n h^{2}

10 x^{2} + 10 x - 698 = 0

(x - 1) (x + 6) (x - 4) \geq 0

- 10 = - 10 + 7 m

2 (x + 5) = 16

What are the solutions to the equation -x^2+9x=x^2-5x ?
The solutions to the equation -x^2+9x=x^2-5x are x=0,x=7
Find the zeros of -x^2+9x=x^2-5x
The zeros of -x^2+9x=x^2-5x are x=0,x=7