What is the answer to solvefor f,f^{-1}(x)=x^3+6 ?

The answer to solvefor f,f^{-1}(x)=x^3+6 is

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solvefor f,f^{-1}(x)=x^3+6

solve for

f, f^{- 1} (x) = x^{3} + 6

Solution steps

f^{- 1} (x) = x^{3} + 6

Refine

\frac{x}{f} = x^{3} + 6

Multiply both sides by

f

x = x^{3} f + 6 f

Switch sides

x^{3} f + 6 f = x

Factor

x^{3} f + 6 f : f (x^{3} + 6)

f (x^{3} + 6) = x

Divide both sides by

f, f^{- 1} (x) = x^{3} - 4

f, f^{- 1} (x) = x^{3} + x

f, f^{- 1} (x) = x^{3} - 2

\frac{4 x + 3}{5 x - 3} = \frac{7}{5}

4 x^{- 6} + 4 x^{- 3} - 15 = 0

What is the answer to solvefor f,f^{-1}(x)=x^3+6 ?
The answer to solvefor f,f^{-1}(x)=x^3+6 is