What is the answer to (x^2-4)/(x^2+3x+2)=0 ?

The answer to (x^2-4)/(x^2+3x+2)=0 is x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2-4)/(x^2+3x+2)=0

\frac{x ^{2} - 4}{x ^{2} + 3 x + 2} = 0

x = 2

Solution steps

\frac{x ^{2} - 4}{x ^{2} + 3 x + 2} = 0

Simplify

\frac{x ^{2} - 4}{x ^{2} + 3 x + 2} : \frac{x - 2}{x + 1}

\frac{x - 2}{x + 1} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

x - 2 = 0

Move

2

to the right side

x = 2

Verify Solutions

Find undefined (singularity) points:

x = - 1, x = - 2

Combine undefined points with solutions:

x = 2

x, z = \frac{x + y}{m x}

\frac{x}{x - 6} + 3 = \frac{6}{x - 6}

x^{2} - 1 = \frac{1}{x}

8 = \frac{10}{r} \cdot r^{2}

\frac{34 + 3 x}{18 + x} = 2.2

What is the answer to (x^2-4)/(x^2+3x+2)=0 ?
The answer to (x^2-4)/(x^2+3x+2)=0 is x=2
Solve for x: (x^2-4)/(x^2+3x+2)=0
The solution is x=2