What is the answer to 6/(x^2+x)=x^2+x+1 ?

The answer to 6/(x^2+x)=x^2+x+1 is x=1,x=-2,x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

Solve for x: 6/(x^2+x)=x^2+x+1

The solution is x=1,x=-2,x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{6}{x ^{2} + x} = x^{2} + x + 1

x = 1, x = - 2, x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

Solution steps

\frac{6}{x ^{2} + x} = x^{2} + x + 1

Multiply both sides by

x^{2} + x

6 = x^{2} (x^{2} + x) + x (x^{2} + x) + x^{2} + x

Solve

6 = x^{2} (x^{2} + x) + x (x^{2} + x) + x^{2} + x : x = 1, x = - 2, x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

x = 1, x = - 2, x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0, x = - 1

Combine undefined points with solutions:

x = 1, x = - 2, x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

\frac{4 x}{20} = \frac{5}{x}

x + \frac{6}{x} = - 7

\frac{3}{x + 1} = - 1

a, u = - \frac{2 a - 3}{ka}

\frac{10}{m} = \frac{5}{11}

What is the answer to 6/(x^2+x)=x^2+x+1 ?
The answer to 6/(x^2+x)=x^2+x+1 is x=1,x=-2,x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2
Solve for x: 6/(x^2+x)=x^2+x+1
The solution is x=1,x=-2,x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2