What is the answer to (9-x^2)/(x^2+3x)=1 ?

The answer to (9-x^2)/(x^2+3x)=1 is x= 3/2

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(9-x^2)/(x^2+3x)=1

\frac{9 - x ^{2}}{x ^{2} + 3 x} = 1

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

\frac{9 - x ^{2}}{x ^{2} + 3 x} = 1

Simplify

\frac{9 - x ^{2}}{x ^{2} + 3 x} : - \frac{x - 3}{x}

- \frac{x - 3}{x} = 1

Multiply both sides by

x

- (x - 3) = x

Expand

- (x - 3) : - x + 3

- x + 3 = x

Move

3

to the right side

- x = x - 3

Move

x

to the left side

- 2 x = - 3

Divide both sides by

- 2

x = \frac{3}{2}

Verify Solutions

Find undefined (singularity) points:

x = 0, x = - 3

Combine undefined points with solutions:

x = \frac{3}{2}

\frac{( x ^{2} - 2 x )}{( x - 1 ) ^{2}} = 0

\frac{3 x + 1}{x + 4} = 2

5 = \frac{40}{x}

295 = 4 8^{2} \frac{( 8 + x )}{11 x + 24}

\frac{42}{t} = 7

What is the answer to (9-x^2)/(x^2+3x)=1 ?
The answer to (9-x^2)/(x^2+3x)=1 is x= 3/2
Solve for x: (9-x^2)/(x^2+3x)=1
The solution is x= 3/2