What is the answer to (2x}{x-3}=\frac{2x+1)/x ?

The answer to (2x}{x-3}=\frac{2x+1)/x is x=-3/5

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(2x}{x-3}=\frac{2x+1)/x

\frac{2 x}{x - 3} = \frac{2 x + 1}{x}

x = - \frac{3}{5}

Solution steps

\frac{2 x}{x - 3} = \frac{2 x + 1}{x}

Cross multiply

2 x^{2} = 2 x^{2} - 5 x - 3

Subtract

2 x^{2} - 5 x

from both sides

2 x^{2} - (2 x^{2} - 5 x) = 2 x^{2} - 5 x - 3 - (2 x^{2} - 5 x)

Simplify

5 x = - 3

Divide both sides by

5

x = - \frac{3}{5}

Verify Solutions

Find undefined (singularity) points:

x = 3, x = 0

Combine undefined points with solutions:

x = - \frac{3}{5}

x^{- n - 1} = \frac{1}{x ^{n - 1}}

\frac{a}{x ^{2}} + b x^{2} = - 21

\frac{1}{x + 2} = x^{3} + 7 x + 7

\frac{3}{1} = \frac{22}{x}

\frac{2}{x + 1} = \frac{5}{x - 3}

What is the answer to (2x}{x-3}=\frac{2x+1)/x ?
The answer to (2x}{x-3}=\frac{2x+1)/x is x=-3/5
Solve for x: (2x}{x-3}=\frac{2x+1)/x
The solution is x=-3/5