What are the solutions to the equation x^2+6x+25=0 ?

The solutions to the equation x^2+6x+25=0 are x=-3+4i,x=-3-4i

Find the zeros of x^2+6x+25=0

The zeros of x^2+6x+25=0 are x=-3+4i,x=-3-4i

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x^{2} + 6 x + 25 = 0

x = - 3 + 4 i, x = - 3 - 4 i

Solution steps

x^{2} + 6 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 25 : 8 i

x_{1, 2} = \frac{- 6 \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 8 i}{2 \cdot 1}, x_{2} = \frac{- 6 - 8 i}{2 \cdot 1}

x = \frac{- 6 + 8 i}{2 \cdot 1} : - 3 + 4 i

x = \frac{- 6 - 8 i}{2 \cdot 1} : - 3 - 4 i

The solutions to the quadratic equation are:

x = - 3 + 4 i, x = - 3 - 4 i

4 x - 9 = - 6 x + 11

8^{2} + 9

2 x + 7 \geq 5

5 x^{2} + 4 = 2 x + 4

540

What are the solutions to the equation x^2+6x+25=0 ?
The solutions to the equation x^2+6x+25=0 are x=-3+4i,x=-3-4i
Find the zeros of x^2+6x+25=0
The zeros of x^2+6x+25=0 are x=-3+4i,x=-3-4i