What is the answer to 5/(y-4)-2/(3y+1)=0 ?

The answer to 5/(y-4)-2/(3y+1)=0 is y=-1

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5/(y-4)-2/(3y+1)=0

\frac{5}{y - 4} - \frac{2}{3 y + 1} = 0

y = - 1

Solution steps

\frac{5}{y - 4} - \frac{2}{3 y + 1} = 0

Multiply by LCM

13 y + 13 = 0

Move

13

to the right side

13 y = - 13

Divide both sides by

13

y = - 1

Verify Solutions

Find undefined (singularity) points:

y = 4, y = - \frac{1}{3}

Combine undefined points with solutions:

y = - 1

\frac{9}{x + 1} + 3 = - 3

\frac{1 + a}{1 - a} = \frac{- 2}{z}

u + u^{- 1} = \frac{5}{2}

\frac{2}{x - 4} + \frac{x + 1}{3} = 5

a^{2} = \frac{- k ^{2}}{1 - k}

What is the answer to 5/(y-4)-2/(3y+1)=0 ?
The answer to 5/(y-4)-2/(3y+1)=0 is y=-1
Solve for y: 5/(y-4)-2/(3y+1)=0
The solution is y=-1