What is the answer to A=(180(n-2))/n ?

The answer to A=(180(n-2))/n is n=-(360)/(A-180);\quad A\ne 180

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A=(180(n-2))/n

A = \frac{180 ( n - 2 )}{n}

n = - \frac{360}{A - 180}; A \neq = 180

Solution steps

A = \frac{180 ( n - 2 )}{n}

Multiply both sides by

n

A n = 180 (n - 2)

Expand

180 (n - 2) : 180 n - 360

A n = 180 n - 360

Move

180 n

to the left side

A n - 180 n = - 360

Factor

A n - 180 n : n (A - 180)

n (A - 180) = - 360

Divide both sides by

A - 180; A \neq = 180

n = - \frac{360}{A - 180}; A \neq = 180

6 t^{- 2} - 5 t^{- 1} + 1 = 0

m, p = \frac{r t}{m v}

g (2) = \frac{n - 1}{n}

\frac{4 ( n + 1 ) !}{( n - 1 ) !} = 168

\frac{2}{x} + \frac{5}{3 x} = 1

What is the answer to A=(180(n-2))/n ?
The answer to A=(180(n-2))/n is n=-(360)/(A-180);\quad A\ne 180