What are the solutions to the equation 3(5x+7)^2-24=-12 ?

The solutions to the equation 3(5x+7)^2-24=-12 are x=-1,x=-9/5

Find the zeros of 3(5x+7)^2-24=-12

The zeros of 3(5x+7)^2-24=-12 are x=-1,x=-9/5

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3 (5 x + 7)^{2} - 24 = - 12

x = - 1, x = - \frac{9}{5}

Solution steps

3 (5 x + 7)^{2} - 24 = - 12

Move

24

to the right side

3 (5 x + 7)^{2} = 12

Divide both sides by

3

(5 x + 7)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 7 = 4 : x = - 1

Solve

5 x + 7 = - 4 : x = - \frac{9}{5}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{9}{5}

4 a^{2} - 20 a + 25 = 0

6 x^{2} + 37 x + 6

- 5 ∣ 2 + 4 x ∣ = - 32 (x + \frac{3}{4}) - ∣ x ∣ + 1

\frac{5 ^{- 3}}{5 ^{6}}

8 x^{3} y + 2 x^{4} - 8 x^{4} y

What are the solutions to the equation 3(5x+7)^2-24=-12 ?
The solutions to the equation 3(5x+7)^2-24=-12 are x=-1,x=-9/5
Find the zeros of 3(5x+7)^2-24=-12
The zeros of 3(5x+7)^2-24=-12 are x=-1,x=-9/5