What is 1/(|x+3|)>5 ?

The solution to 1/(|x+3|)>5 is -16/5 <x<-3\lor-3<x<-14/5

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1/(|x+3|)>5

\frac{1}{∣ x + 3 ∣} > 5

- \frac{16}{5} < x < - 3 or - 3 < x < - \frac{14}{5}

Solution steps

\frac{1}{∣ x + 3 ∣} > 5

Find positive and negative intervals

x < - 3, x \geq - 3

Solve the inequality for each interval

- \frac{16}{5} < x < - 3 or - 3 < x < - \frac{14}{5}

m^{2} - 6 mn - 27 n^{2}

\frac{y}{3} + 6 = 9

∣ y - 5 ∣ = 3

- x^{2} + 12 x - 20 = 0

18 x^{2} - 54 x + 36 = 0