What is the answer to solvefor y,x=(5y+1)/(2y-3) ?

The answer to solvefor y,x=(5y+1)/(2y-3) is y=(1+3x)/(2x-5);\quad x\ne 5/2

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solvefor y,x=(5y+1)/(2y-3)

solve for

y, x = \frac{5 y + 1}{2 y - 3}

y = \frac{1 + 3 x}{2 x - 5}; x \neq = \frac{5}{2}

Solution steps

x = \frac{5 y + 1}{2 y - 3}

Multiply both sides by

2 y - 3

x (2 y - 3) = 5 y + 1

Expand

x (2 y - 3) : 2 y x - 3 x

2 y x - 3 x = 5 y + 1

Move

3 x

to the right side

2 y x = 5 y + 1 + 3 x

Move

5 y

to the left side

2 y x - 5 y = 1 + 3 x

Factor

2 y x - 5 y : y (2 x - 5)

y (2 x - 5) = 1 + 3 x

Divide both sides by

2 x - 5; x \neq = \frac{5}{2}

y = \frac{1 + 3 x}{2 x - 5}; x \neq = \frac{5}{2}

\frac{x}{2 x - 4} - 5 = \frac{1}{x - 2}

\frac{2 x}{x + 1} = 2 - \frac{5}{2 x}

\frac{8}{7} = \frac{4}{x}

j, a = \frac{j + b}{j - c}

y, y = \frac{6}{y}

What is the answer to solvefor y,x=(5y+1)/(2y-3) ?
The answer to solvefor y,x=(5y+1)/(2y-3) is y=(1+3x)/(2x-5);\quad x\ne 5/2