What is the answer to (3x+2)/(x^2+7x+12)=0 ?

The answer to (3x+2)/(x^2+7x+12)=0 is x=-2/3

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(3x+2)/(x^2+7x+12)=0

\frac{3 x + 2}{x ^{2} + 7 x + 12} = 0

x = - \frac{2}{3}

Decimal Notation

x = - 0.66666 \dots

Solution steps

\frac{3 x + 2}{x ^{2} + 7 x + 12} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 x + 2 = 0

Move

2

to the right side

3 x = - 2

Divide both sides by

3

x = - \frac{2}{3}

Verify Solutions

Find undefined (singularity) points:

x = - 3, x = - 4

Combine undefined points with solutions:

x = - \frac{2}{3}

400 y^{- 4} - 41 y^{- 2} + 1 = 0

\frac{6}{9} = \frac{8}{x}

\frac{x}{x - 2} + 6 = \frac{2}{x - 2}

g, p = \frac{d}{r - g}

x, m = \frac{y}{x}

What is the answer to (3x+2)/(x^2+7x+12)=0 ?
The answer to (3x+2)/(x^2+7x+12)=0 is x=-2/3
Solve for x: (3x+2)/(x^2+7x+12)=0
The solution is x=-2/3