What is the answer to solvefor y,x= 2/(y-3) ?

The answer to solvefor y,x= 2/(y-3) is y= 2/x+3;\quad x\ne 0

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solvefor y,x= 2/(y-3)

solve for

y, x = \frac{2}{y - 3}

y = \frac{2}{x} + 3; x \neq = 0

Solution steps

x = \frac{2}{y - 3}

Multiply both sides by

y - 3

x (y - 3) = 2

Divide both sides by

x; x \neq = 0

y - 3 = \frac{2}{x}; x \neq = 0

Move

3

to the right side

y = \frac{2}{x} + 3; x \neq = 0

\frac{( k - 1 ) ^{6} - 1}{3 k} = 7

t, s = \frac{d}{t - t o}

\frac{1}{x - 1} + \frac{2 x}{x - 1} = 5

\frac{8 - 4 x}{x - 2} = x

\frac{2 k}{k - 1} = \frac{21 - k}{2 k}

What is the answer to solvefor y,x= 2/(y-3) ?
The answer to solvefor y,x= 2/(y-3) is y= 2/x+3;\quad x\ne 0