What is the answer to 0.2=(9t)/(t^2+4) ?

The answer to 0.2=(9t)/(t^2+4) is t=(45+7sqrt(41))/2 ,t=(45-7sqrt(41))/2

Solve for t: 0.2=(9t)/(t^2+4)

The solution is t=(45+7sqrt(41))/2 ,t=(45-7sqrt(41))/2

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0.2 = \frac{9 t}{t ^{2} + 4}

t = \frac{45 + 7 41}{2}, t = \frac{45 - 7 41}{2}

Decimal Notation

t = 44.91093 \dots, t = 0.08906 \dots

Solution steps

0.2 = \frac{9 t}{t ^{2} + 4}

Multiply both sides by

t^{2} + 4

0.2 (t^{2} + 4) = 9 t

Solve

0.2 (t^{2} + 4) = 9 t : t = \frac{45 + 7 41}{2}, t = \frac{45 - 7 41}{2}

t = \frac{45 + 7 41}{2}, t = \frac{45 - 7 41}{2}

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4 = \frac{3}{2 - x} + \frac{3}{2 + x}

18 = \frac{1000}{0.707 h ( 3.5 )}

x, \frac{- 1}{x ^{2}} = 0

- \frac{3}{x} = \frac{11}{3 x} - 5

What is the answer to 0.2=(9t)/(t^2+4) ?
The answer to 0.2=(9t)/(t^2+4) is t=(45+7sqrt(41))/2 ,t=(45-7sqrt(41))/2
Solve for t: 0.2=(9t)/(t^2+4)
The solution is t=(45+7sqrt(41))/2 ,t=(45-7sqrt(41))/2