What are the solutions to the equation x^2+x-2=0 ?

The solutions to the equation x^2+x-2=0 are x=1,x=-2

Find the zeros of x^2+x-2=0

The zeros of x^2+x-2=0 are x=1,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + x - 2 = 0

x = 1, x = - 2

Solution steps

x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 \cdot 1}, x_{2} = \frac{- 1 - 3}{2 \cdot 1}

x = \frac{- 1 + 3}{2 \cdot 1} : 1

x = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

25 n^{2} - 9

\frac{6 w - 1}{5} - 3 w = \frac{12 w - 16}{15}

i^{- 3} + 3 i^{7}

n^{2} + 24 n + 144

720 = (2 x - 4) (x)

What are the solutions to the equation x^2+x-2=0 ?
The solutions to the equation x^2+x-2=0 are x=1,x=-2
Find the zeros of x^2+x-2=0
The zeros of x^2+x-2=0 are x=1,x=-2