What is the answer to solvefor t,g=(2h)/(t^2) ?

The answer to solvefor t,g=(2h)/(t^2) is t=sqrt((2h)/g),t=-sqrt((2h)/g);\quad g\ne 0

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solvefor t,g=(2h)/(t^2)

solve for

t, g = \frac{2 h}{t ^{2}}

t = \frac{2 h}{g}, t = - \frac{2 h}{g}; g \neq = 0

Solution steps

g = \frac{2 h}{t ^{2}}

Multiply both sides by

t^{2}

g t^{2} = 2 h

Solve

g t^{2} = 2 h : t = \frac{2 h}{g}, t = - \frac{2 h}{g}; g \neq = 0

t = \frac{2 h}{g}, t = - \frac{2 h}{g}; g \neq = 0

1 - \frac{1}{k ^{2}} = 0.81

1 - \frac{1}{k ^{2}} = 0.89

\frac{16}{14} = \frac{8}{x}

\frac{12}{x} = \frac{22}{66}

\frac{( 2 x - 6 ) ( x - 4 )}{x + 3} = 0

What is the answer to solvefor t,g=(2h)/(t^2) ?
The answer to solvefor t,g=(2h)/(t^2) is t=sqrt((2h)/g),t=-sqrt((2h)/g);\quad g\ne 0