What is 4(3h-11)<= 6(2h-3)+19 ?

The solution to 4(3h-11)<= 6(2h-3)+19 is True for all h

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4(3h-11)<= 6(2h-3)+19

4 (3 h - 11) \leq 6 (2 h - 3) + 19

True for all h

Solution steps

4 (3 h - 11) \leq 6 (2 h - 3) + 19

Expand

4 (3 h - 11) : 12 h - 44

Expand

6 (2 h - 3) + 19 : 12 h + 1

12 h - 44 \leq 12 h + 1

Move

44

to the right side

12 h \leq 12 h + 45

Move

12 h

to the left side

0 \leq 45

Therefore, the solution is

True for all h

1 x^{2} - 2 x - 1 = 0

y^{\frac{2}{9}} \cdot y^{\frac{5}{18}}

2 ∣ x + 4 ∣ - 6 = 14

48 y - 13 + 12 y = 72 y - 3 - 24 y

\frac{8}{4} \cdot \frac{4}{12}

What is 4(3h-11)<= 6(2h-3)+19 ?
The solution to 4(3h-11)<= 6(2h-3)+19 is True for all h