What are the solutions to the equation 1x^2-2x-1=0 ?

The solutions to the equation 1x^2-2x-1=0 are x=1+sqrt(2),x=1-sqrt(2)

Find the zeros of 1x^2-2x-1=0

The zeros of 1x^2-2x-1=0 are x=1+sqrt(2),x=1-sqrt(2)

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1 x^{2} - 2 x - 1 = 0

x = 1 + 2, x = 1 - 2

Decimal Notation

x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

1 \cdot x^{2} - 2 x - 1 = 0

Refine

x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 1) = 22

x_{1, 2} = \frac{- ( - 2 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 2}{2 \cdot 1} : 1 + 2

x = \frac{- ( - 2 ) - 2 2}{2 \cdot 1} : 1 - 2

The solutions to the quadratic equation are:

x = 1 + 2, x = 1 - 2

y^{\frac{2}{9}} \cdot y^{\frac{5}{18}}

2 ∣ x + 4 ∣ - 6 = 14

48 y - 13 + 12 y = 72 y - 3 - 24 y

\frac{8}{4} \cdot \frac{4}{12}

25 - (x^{2} + 4 x + 4)

What are the solutions to the equation 1x^2-2x-1=0 ?
The solutions to the equation 1x^2-2x-1=0 are x=1+sqrt(2),x=1-sqrt(2)
Find the zeros of 1x^2-2x-1=0
The zeros of 1x^2-2x-1=0 are x=1+sqrt(2),x=1-sqrt(2)