What are the solutions to the equation (x+3)(x+5)=3 ?

The solutions to the equation (x+3)(x+5)=3 are x=-2,x=-6

Find the zeros of (x+3)(x+5)=3

The zeros of (x+3)(x+5)=3 are x=-2,x=-6

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(x + 3) (x + 5) = 3

x = - 2, x = - 6

Solution steps

(x + 3) (x + 5) = 3

Expand

(x + 3) (x + 5) : x^{2} + 8 x + 15

x^{2} + 8 x + 15 = 3

Move

3

to the left side

x^{2} + 8 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 12 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 1}, x_{2} = \frac{- 8 - 4}{2 \cdot 1}

x = \frac{- 8 + 4}{2 \cdot 1} : - 2

x = \frac{- 8 - 4}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 2, x = - 6

- 2 (\frac{1}{2})

x x^{5}

27 a b^{3}

a - a = - 5

x^{2} + 6 = - 6 x

What are the solutions to the equation (x+3)(x+5)=3 ?
The solutions to the equation (x+3)(x+5)=3 are x=-2,x=-6
Find the zeros of (x+3)(x+5)=3
The zeros of (x+3)(x+5)=3 are x=-2,x=-6