What are the solutions to the equation x^2+6=-6x ?

The solutions to the equation x^2+6=-6x are x=-3+sqrt(3),x=-3-sqrt(3)

Find the zeros of x^2+6=-6x

The zeros of x^2+6=-6x are x=-3+sqrt(3),x=-3-sqrt(3)

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x^{2} + 6 = - 6 x

x = - 3 + 3, x = - 3 - 3

Solution steps

x^{2} + 6 = - 6 x

Move

6 x

to the left side

x^{2} + 6 + 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 6 = 23

x_{1, 2} = \frac{- 6 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 3}{2 \cdot 1}

x = \frac{- 6 + 2 3}{2 \cdot 1} : - 3 + 3

x = \frac{- 6 - 2 3}{2 \cdot 1} : - 3 - 3

The solutions to the quadratic equation are:

x = - 3 + 3, x = - 3 - 3

- 3 x^{- 3}

\frac{16 m ^{- 5} n ^{4}}{12 m ^{2} n ^{- 3}}

r - 14 \geq 17

\frac{( 1 + i )}{( 1 - i )}

\frac{( 3 ab ) ^{3}}{2 a b ^{2} ( 6 a ) ^{2}}

What are the solutions to the equation x^2+6=-6x ?
The solutions to the equation x^2+6=-6x are x=-3+sqrt(3),x=-3-sqrt(3)
Find the zeros of x^2+6=-6x
The zeros of x^2+6=-6x are x=-3+sqrt(3),x=-3-sqrt(3)