What is the answer to (c^2+6c-27)/(c-3)+2c=23 ?

The answer to (c^2+6c-27)/(c-3)+2c=23 is c= 14/3

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(c^2+6c-27)/(c-3)+2c=23

\frac{c ^{2} + 6 c - 27}{c - 3} + 2 c = 23

c = \frac{14}{3}

Decimal Notation

c = 4.66666 \dots

Solution steps

\frac{c ^{2} + 6 c - 27}{c - 3} + 2 c = 23

Simplify

\frac{c ^{2} + 6 c - 27}{c - 3} : c + 9

c + 9 + 2 c = 23

Group like terms

c + 2 c + 9 = 23

Add similar elements:

c + 2 c = 3 c

3 c + 9 = 23

Move

9

to the right side

3 c = 14

Divide both sides by

3

c = \frac{14}{3}

Verify Solutions

Find undefined (singularity) points:

c = 3

Combine undefined points with solutions:

c = \frac{14}{3}

\frac{4}{3 - x} + \frac{1}{1 - x} = 0

\frac{6 x ^{2} + 12}{3 x - 4} = 2 x

\frac{x - 1}{x - 3} = 0

\frac{20}{x - 1} = 2 x + 3

\frac{r}{2} - 1 = \frac{4}{r}

What is the answer to (c^2+6c-27)/(c-3)+2c=23 ?
The answer to (c^2+6c-27)/(c-3)+2c=23 is c= 14/3
Solve for c: (c^2+6c-27)/(c-3)+2c=23
The solution is c= 14/3