What is the answer to 3(4^x)=4(5^{2x-7}) ?

The answer to 3(4^x)=4(5^{2x-7}) is x=-(7ln(5)+ln(3)-2ln(2))/(2(ln(2)-ln(5)))

Solve for x: 3(4^x)=4(5^{2x-7})

The solution is x=-(7ln(5)+ln(3)-2ln(2))/(2(ln(2)-ln(5)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (4^{x}) = 4 (5^{2 x - 7})

x = - \frac{7 ln ( 5 ) + ln ( 3 ) - 2 ln ( 2 )}{2 ( ln ( 2 ) - ln ( 5 ) )}

Decimal Notation

x = 5.99066 \dots

Solution steps

3 (4^{x}) = 4 (5^{2 x - 7})

Apply exponent rules

ln (3) + x ln (4) = ln (4) + (2 x - 7) ln (5)

Solve

ln (3) + x ln (4) = ln (4) + (2 x - 7) ln (5) : x = - \frac{7 ln ( 5 ) + ln ( 3 ) - 2 ln ( 2 )}{2 ( ln ( 2 ) - ln ( 5 ) )}

x = - \frac{7 ln ( 5 ) + ln ( 3 ) - 2 ln ( 2 )}{2 ( ln ( 2 ) - ln ( 5 ) )}

2^{x - 5} = 3

7 (3^{x}) = 2 (4^{5 x - 4})

7 (3^{x}) = 3 (5^{5 x - 4})

3 (4^{x}) = 5 (7^{2 x - 2})

6 (4^{x}) = 5 (3^{3 x - 5})

What is the answer to 3(4^x)=4(5^{2x-7}) ?
The answer to 3(4^x)=4(5^{2x-7}) is x=-(7ln(5)+ln(3)-2ln(2))/(2(ln(2)-ln(5)))
Solve for x: 3(4^x)=4(5^{2x-7})
The solution is x=-(7ln(5)+ln(3)-2ln(2))/(2(ln(2)-ln(5)))