What is the answer to 4(3^x)=3(6^{3x-3}) ?

The answer to 4(3^x)=3(6^{3x-3}) is x=(ln(288))/(ln(72))

Solve for x: 4(3^x)=3(6^{3x-3})

The solution is x=(ln(288))/(ln(72))

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4 (3^{x}) = 3 (6^{3 x - 3})

x = \frac{ln ( 288 )}{ln ( 72 )}

Decimal Notation

x = 1.32415 \dots

Solution steps

4 (3^{x}) = 3 (6^{3 x - 3})

Apply exponent rules

ln (4) + x ln (3) = ln (3) + (3 x - 3) ln (6)

Solve

ln (4) + x ln (3) = ln (3) + (3 x - 3) ln (6) : x = \frac{ln ( 288 )}{ln ( 72 )}

x = \frac{ln ( 288 )}{ln ( 72 )}

3^{3 x} = 7^{2 x + 1}

4^{x} = 8

2^{1 - x^{2}} = \frac{1}{8}

e^{2 x} - e^{x} - 6 = 0

4^{x + 1} + 2^{x + 3} = 320

What is the answer to 4(3^x)=3(6^{3x-3}) ?
The answer to 4(3^x)=3(6^{3x-3}) is x=(ln(288))/(ln(72))
Solve for x: 4(3^x)=3(6^{3x-3})
The solution is x=(ln(288))/(ln(72))