What is the answer to 2^{x+1}+2^x+2^{x-1}=28 ?

The answer to 2^{x+1}+2^x+2^{x-1}=28 is x=3

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2^{x+1}+2^x+2^{x-1}=28

2^{x + 1} + 2^{x} + 2^{x - 1} = 28

x = 3

Solution steps

2^{x + 1} + 2^{x} + 2^{x - 1} = 28

Factor

2^{x + 1} + 2^{x} + 2^{x - 1} : 7 \cdot 2^{x - 1}

7 \cdot 2^{x - 1} = 28

Divide both sides by

7

2^{x - 1} = 4

Apply exponent rules

x - 1 = 2

Solve

x - 1 = 2 : x = 3

x = 3

129 6^{2 x - 4} = 21 6^{2 x - 4}

(\frac{1}{2})^{x} = 32

2^{x} = 20

e^{x} = 2 e^{- x} + 1

7^{\frac{x}{2}} = 5^{1 - x}

What is the answer to 2^{x+1}+2^x+2^{x-1}=28 ?
The answer to 2^{x+1}+2^x+2^{x-1}=28 is x=3
Solve for x: 2^{x+1}+2^x+2^{x-1}=28
The solution is x=3