What is the answer to 2^{x+1}=5^{1-2x} ?

The answer to 2^{x+1}=5^{1-2x} is x=(ln(5)-ln(2))/(ln(50))

Solve for x: 2^{x+1}=5^{1-2x}

The solution is x=(ln(5)-ln(2))/(ln(50))

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2^{x + 1} = 5^{1 - 2 x}

x = \frac{ln ( 5 ) - ln ( 2 )}{ln ( 50 )}

Solution steps

2^{x + 1} = 5^{1 - 2 x}

Apply exponent rules

(x + 1) ln (2) = (1 - 2 x) ln (5)

Solve

(x + 1) ln (2) = (1 - 2 x) ln (5) : x = \frac{ln ( 5 ) - ln ( 2 )}{ln ( 50 )}

x = \frac{ln ( 5 ) - ln ( 2 )}{ln ( 50 )}

8 1^{x} = 3

2 5^{x} = \frac{e}{5 ^{3 x}}

2^{3 x} = 10

3^{x} = 10

What is the answer to 2^{x+1}=5^{1-2x} ?
The answer to 2^{x+1}=5^{1-2x} is x=(ln(5)-ln(2))/(ln(50))
Solve for x: 2^{x+1}=5^{1-2x}
The solution is x=(ln(5)-ln(2))/(ln(50))