What is the answer to \sqrt[7]{2^{3x-1}}=32 ?

The answer to \sqrt[7]{2^{3x-1}}=32 is x=12

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\sqrt[7]{2^{3x-1}}=32

x = 12

Solution steps

Apply exponent rules

(3 x - 1) \frac{1}{7} = 5

Solve

(3 x - 1) \frac{1}{7} = 5 : x = 12

x = 12

2^{3 x} = 10

3^{x} = 10

5^{x} = 7

2 5^{x} = 125

2^{x - 1} = 3^{x}

What is the answer to \sqrt[7]{2^{3x-1}}=32 ?
The answer to \sqrt[7]{2^{3x-1}}=32 is x=12
Solve for x: \sqrt[7]{2^{3x-1}}=32
The solution is x=12