What is (-3c^4-5c^2-7c)+(4c^4+8c^3+2c^2) ?

The solution to (-3c^4-5c^2-7c)+(4c^4+8c^3+2c^2) is c^4+8c^3-3c^2-7c

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simplify (-3c^4-5c^2-7c)+(4c^4+8c^3+2c^2)

simplify

(- 3 c^{4} - 5 c^{2} - 7 c) + (4 c^{4} + 8 c^{3} + 2 c^{2})

c^{4} + 8 c^{3} - 3 c^{2} - 7 c

Solution steps

(- 3 c^{4} - 5 c^{2} - 7 c) + (4 c^{4} + 8 c^{3} + 2 c^{2})

Simplify

(- 3 c^{4} - 5 c^{2} - 7 c) + (4 c^{4} + 8 c^{3} + 2 c^{2}) : - 3 c^{4} - 5 c^{2} - 7 c + 4 c^{4} + 8 c^{3} + 2 c^{2}

= - 3 c^{4} - 5 c^{2} - 7 c + 4 c^{4} + 8 c^{3} + 2 c^{2}

Group like terms

= - 3 c^{4} + 4 c^{4} + 8 c^{3} - 5 c^{2} + 2 c^{2} - 7 c

Add similar elements:

- 3 c^{4} + 4 c^{4} = c^{4}

= c^{4} + 8 c^{3} - 5 c^{2} + 2 c^{2} - 7 c

Add similar elements:

- 5 c^{2} + 2 c^{2} = - 3 c^{2}

= c^{4} + 8 c^{3} - 3 c^{2} - 7 c

\frac{2 ( x + 3 )}{5} + \frac{3 ( x - 6 )}{2} = \frac{2}{5} + \frac{10 ( 2 x + 1 )}{6}

2 x - 4 = 2

(8 w - 4)^{2} = 0

x + 12 \leq - \frac{1}{3} or x + 12 \geq \frac{1}{3}

(3 x + 4) 2 = 9

What is (-3c^4-5c^2-7c)+(4c^4+8c^3+2c^2) ?
The solution to (-3c^4-5c^2-7c)+(4c^4+8c^3+2c^2) is c^4+8c^3-3c^2-7c