What is the answer to 4-3^x=0 ?

The answer to 4-3^x=0 is x=(2ln(2))/(ln(3))

The solution is x=(2ln(2))/(ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4-3^x=0

4 - 3^{x} = 0

x = \frac{2 ln ( 2 )}{ln ( 3 )}

Solution steps

4 - 3^{x} = 0

Add

3^{x}

to both sides

4 - 3^{x} + 3^{x} = 0 + 3^{x}

Simplify

4 = 3^{x}

Apply exponent rules

ln (4) = x ln (3)

Solve

ln (4) = x ln (3) : x = \frac{2 ln ( 2 )}{ln ( 3 )}

x = \frac{2 ln ( 2 )}{ln ( 3 )}

1 6^{2 x + 1} = 9^{3 x - 4}

1 6^{2 x - 3} 4^{- 2 x} = 16

13 e^{x} = 2 \cdot 3^{- x}

1 0^{x} = 3

4^{y - 2} = \frac{1}{3 ^{- y}}