What is the answer to 8^{x-1}=6^{3x} ?

The answer to 8^{x-1}=6^{3x} is x=-(ln(2))/(ln(3))

Solve for x: 8^{x-1}=6^{3x}

The solution is x=-(ln(2))/(ln(3))

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8^{x - 1} = 6^{3 x}

x = - \frac{ln ( 2 )}{ln ( 3 )}

Decimal Notation

x = - 0.63092 \dots

Solution steps

8^{x - 1} = 6^{3 x}

Apply exponent rules

(x - 1) ln (8) = 3 x ln (6)

Solve

(x - 1) ln (8) = 3 x ln (6) : x = - \frac{ln ( 2 )}{ln ( 3 )}

x = - \frac{ln ( 2 )}{ln ( 3 )}

e^{3 x} - e^{6 x} = 0

e^{2 x} - 3 e^{x} - 10 = 0

9^{x - 1} = (\frac{1}{3})^{2 x}

4 - (6^{5 - 3 x}) = - 5

e^{2 x} + e^{x} = 12

What is the answer to 8^{x-1}=6^{3x} ?
The answer to 8^{x-1}=6^{3x} is x=-(ln(2))/(ln(3))
Solve for x: 8^{x-1}=6^{3x}
The solution is x=-(ln(2))/(ln(3))