What is the answer to 9^{x-1}=(1/3)^{2x} ?

The answer to 9^{x-1}=(1/3)^{2x} is x= 1/2

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9^{x-1}=(1/3)^{2x}

9^{x - 1} = (\frac{1}{3})^{2 x}

x = \frac{1}{2}

Solution steps

9^{x - 1} = (\frac{1}{3})^{2 x}

Apply exponent rules

2 (x - 1) = - 2 x

Solve

2 (x - 1) = - 2 x : x = \frac{1}{2}

x = \frac{1}{2}

4 - (6^{5 - 3 x}) = - 5

e^{2 x} + e^{x} = 12

1 6^{x} = 8

2^{3 x - 1} = 5^{x - 2}

7^{3 - x} = 5^{x + 1}

What is the answer to 9^{x-1}=(1/3)^{2x} ?
The answer to 9^{x-1}=(1/3)^{2x} is x= 1/2
Solve for x: 9^{x-1}=(1/3)^{2x}
The solution is x= 1/2