What is the answer to 2^{2x+1}*4^{3x+1}=8^{x-1} ?

The answer to 2^{2x+1}*4^{3x+1}=8^{x-1} is x=-6/5

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2^{2x+1}*4^{3x+1}=8^{x-1}

2^{2 x + 1} \cdot 4^{3 x + 1} = 8^{x - 1}

x = - \frac{6}{5}

Solution steps

2^{2 x + 1} \cdot 4^{3 x + 1} = 8^{x - 1}

Apply exponent rules

2 x + 1 + 2 (3 x + 1) = 3 (x - 1)

Solve

2 x + 1 + 2 (3 x + 1) = 3 (x - 1) : x = - \frac{6}{5}

x = - \frac{6}{5}

e^{x} + e^{- x} = 0

e^{e^{x}} = 10

2^{3 x} = 256

5^{x} = \frac{1}{625}

3^{1 - 2 x} = 4^{x}

What is the answer to 2^{2x+1}*4^{3x+1}=8^{x-1} ?
The answer to 2^{2x+1}*4^{3x+1}=8^{x-1} is x=-6/5
Solve for x: 2^{2x+1}*4^{3x+1}=8^{x-1}
The solution is x=-6/5