What is the answer to 5^{x+2}=4^x ?

The answer to 5^{x+2}=4^x is x=-(2ln(5))/(ln(5)-2ln(2))

Solve for x: 5^{x+2}=4^x

The solution is x=-(2ln(5))/(ln(5)-2ln(2))

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5^{x + 2} = 4^{x}

x = - \frac{2 ln ( 5 )}{ln ( 5 ) - 2 ln ( 2 )}

Decimal Notation

x = - 14.42513 \dots

Solution steps

5^{x + 2} = 4^{x}

Apply exponent rules

(x + 2) ln (5) = x ln (4)

Solve

(x + 2) ln (5) = x ln (4) : x = - \frac{2 ln ( 5 )}{ln ( 5 ) - 2 ln ( 2 )}

x = - \frac{2 ln ( 5 )}{ln ( 5 ) - 2 ln ( 2 )}

9^{x} = 3

8^{2 x + 1} = 1 6^{2 x - 3}

3^{x} = \frac{1}{3}

200 = 100 e^{r (6)}

3^{3 x - 4} = 15

What is the answer to 5^{x+2}=4^x ?
The answer to 5^{x+2}=4^x is x=-(2ln(5))/(ln(5)-2ln(2))
Solve for x: 5^{x+2}=4^x
The solution is x=-(2ln(5))/(ln(5)-2ln(2))