What is the answer to 3^{x+2}=63 ?

The answer to 3^{x+2}=63 is x=(ln(63))/(ln(3))-2

Solve for x: 3^{x+2}=63

The solution is x=(ln(63))/(ln(3))-2

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3^{x + 2} = 63

x = \frac{ln ( 63 )}{ln ( 3 )} - 2

Decimal Notation

x = 1.77124 \dots

Solution steps

3^{x + 2} = 63

Apply exponent rules

(x + 2) ln (3) = ln (63)

Solve

(x + 2) ln (3) = ln (63) : x = \frac{ln ( 63 )}{ln ( 3 )} - 2

x = \frac{ln ( 63 )}{ln ( 3 )} - 2

4^{x + 4} - 4^{x + 3} = 96

e^{x} + 5 e^{- x} = 6

2^{x} = 14

6 - 5^{x} = 5^{1 - x}

(\frac{9}{8})^{3 x + 12} = 1

What is the answer to 3^{x+2}=63 ?
The answer to 3^{x+2}=63 is x=(ln(63))/(ln(3))-2
Solve for x: 3^{x+2}=63
The solution is x=(ln(63))/(ln(3))-2