What is the answer to 5(3^x)-420=0 ?

The answer to 5(3^x)-420=0 is x=(ln(84))/(ln(3))

Solve for x: 5(3^x)-420=0

The solution is x=(ln(84))/(ln(3))

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5 (3^{x}) - 420 = 0

x = \frac{ln ( 84 )}{ln ( 3 )}

Solution steps

5 (3^{x}) - 420 = 0

Add

420

to both sides

5 \cdot 3^{x} - 420 + 420 = 0 + 420

Simplify

5 \cdot 3^{x} = 420

Divide both sides by

5

3^{x} = 84

Apply exponent rules

x ln (3) = ln (84)

Solve

x ln (3) = ln (84) : x = \frac{ln ( 84 )}{ln ( 3 )}

x = \frac{ln ( 84 )}{ln ( 3 )}

e^{2 x} - 11 e^{x} + 30 = 0

7^{x} = 5

7^{x} = 3

7^{x} = 2

7^{x} = 1

What is the answer to 5(3^x)-420=0 ?
The answer to 5(3^x)-420=0 is x=(ln(84))/(ln(3))
Solve for x: 5(3^x)-420=0
The solution is x=(ln(84))/(ln(3))