What is the answer to 7^{2x+1}-2*7^{x+1}+7=0 ?

The answer to 7^{2x+1}-2*7^{x+1}+7=0 is x=0

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7^{2x+1}-2*7^{x+1}+7=0

7^{2 x + 1} - 2 \cdot 7^{x + 1} + 7 = 0

x = 0

Solution steps

7^{2 x + 1} - 2 \cdot 7^{x + 1} + 7 = 0

Apply exponent rules

(7^{x})^{2} \cdot 7^{1} - 2 \cdot 7^{x} \cdot 7^{1} + 7 = 0

Rewrite the equation with

7^{x} = u

(u)^{2} \cdot 7^{1} - 2 u \cdot 7^{1} + 7 = 0

Solve

u^{2} \cdot 7^{1} - 2 u \cdot 7^{1} + 7 = 0 : u = 1

u = 1

Substitute back

u = 7^{x},

solve for

x

Solve

7^{x} = 1 : x = 0

x = 0

5^{2 x} - 30 (5^{x}) + 125 = 0

e^{2 x} - 5 = 0

2 6^{9 x + 5} = 1

(\frac{1}{3})^{x - 1} = 27

x, y^{3 x} = n + 1

What is the answer to 7^{2x+1}-2*7^{x+1}+7=0 ?
The answer to 7^{2x+1}-2*7^{x+1}+7=0 is x=0
Solve for x: 7^{2x+1}-2*7^{x+1}+7=0
The solution is x=0