What is the answer to 4^{log_{4}(x)+log_{4}(2)}=3 ?

The answer to 4^{log_{4}(x)+log_{4}(2)}=3 is x=4^{(ln(3))/(2ln(2))-1/2}

Solve for x: 4^{log_{4}(x)+log_{4}(2)}=3

The solution is x=4^{(ln(3))/(2ln(2))-1/2}

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4^{l o g_{4} (x) + l o g_{4} (2)} = 3

x = 4^{\frac{l n ( 3 )}{2 l n ( 2 )} - \frac{1}{2}}

Decimal Notation

x = 1.5

Solution steps

4^{l o g_{4} (x) + l o g_{4} (2)} = 3

Apply exponent rules

(lo g_{4} (x) + lo g_{4} (2)) ln (4) = ln (3)

Solve

(lo g_{4} (x) + lo g_{4} (2)) ln (4) = ln (3) : x = 4^{\frac{l n ( 3 )}{2 l n ( 2 )} - \frac{1}{2}}

x = 4^{\frac{l n ( 3 )}{2 l n ( 2 )} - \frac{1}{2}}

5^{x} = 30

9^{x} = (\frac{1}{27})^{x - 2}

9^{x + 1} = 2 7^{3 x - 4}

e^{2 x} - 10 e^{x} + 9 = 0

5^{2 x} = 2 5^{4 - x}

What is the answer to 4^{log_{4}(x)+log_{4}(2)}=3 ?
The answer to 4^{log_{4}(x)+log_{4}(2)}=3 is x=4^{(ln(3))/(2ln(2))-1/2}
Solve for x: 4^{log_{4}(x)+log_{4}(2)}=3
The solution is x=4^{(ln(3))/(2ln(2))-1/2}