What is the answer to 49^{x+3}=7^{x^2-3x-8} ?

The answer to 49^{x+3}=7^{x^2-3x-8} is x=7,x=-2

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49^{x+3}=7^{x^2-3x-8}

4 9^{x + 3} = 7^{x^{2} - 3 x - 8}

x = 7, x = - 2

Solution steps

4 9^{x + 3} = 7^{x^{2} - 3 x - 8}

Apply exponent rules

2 (x + 3) = x^{2} - 3 x - 8

Solve

2 (x + 3) = x^{2} - 3 x - 8 : x = 7, x = - 2

x = 7, x = - 2

1 + 9^{x} = 3^{x + 1} + 3^{x - 1}

\frac{9 ^{x}}{9 ^{3}} = 9^{5}

6^{x} = 12

3^{x + 1} = 8

1 9^{x} = 0

What is the answer to 49^{x+3}=7^{x^2-3x-8} ?
The answer to 49^{x+3}=7^{x^2-3x-8} is x=7,x=-2
Solve for x: 49^{x+3}=7^{x^2-3x-8}
The solution is x=7,x=-2