What is the answer to 3^{x+1}=8 ?

The answer to 3^{x+1}=8 is x=(3ln(2))/(ln(3))-1

Solve for x: 3^{x+1}=8

The solution is x=(3ln(2))/(ln(3))-1

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3^{x + 1} = 8

x = \frac{3 ln ( 2 )}{ln ( 3 )} - 1

Decimal Notation

x = 0.89278 \dots

Solution steps

3^{x + 1} = 8

Apply exponent rules

(x + 1) ln (3) = ln (8)

Solve

(x + 1) ln (3) = ln (8) : x = \frac{3 ln ( 2 )}{ln ( 3 )} - 1

x = \frac{3 ln ( 2 )}{ln ( 3 )} - 1

1 9^{x} = 0

2^{2 x} - 5 \cdot 2^{x + 2} + 64 = 0

7^{5 x - 2} = 343

4^{x} = \frac{1}{4}

4 (2^{2 x}) = 8 (2^{x}) - 4

What is the answer to 3^{x+1}=8 ?
The answer to 3^{x+1}=8 is x=(3ln(2))/(ln(3))-1
Solve for x: 3^{x+1}=8
The solution is x=(3ln(2))/(ln(3))-1