What is the answer to 3^{x+1}=15 ?

The answer to 3^{x+1}=15 is x=(ln(15))/(ln(3))-1

Solve for x: 3^{x+1}=15

The solution is x=(ln(15))/(ln(3))-1

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3^{x + 1} = 15

x = \frac{ln ( 15 )}{ln ( 3 )} - 1

Decimal Notation

x = 1.46497 \dots

Solution steps

3^{x + 1} = 15

Apply exponent rules

(x + 1) ln (3) = ln (15)

Solve

(x + 1) ln (3) = ln (15) : x = \frac{ln ( 15 )}{ln ( 3 )} - 1

x = \frac{ln ( 15 )}{ln ( 3 )} - 1

4^{x + 1} = 8

2 5^{x^{2} - 3 x + 7} = 12 5^{x - 2}

4^{x} - 9 \cdot 2^{x - 1} + 2 = 0

2 e^{2 x} - e^{x} = 0

0 = e^{- x}

What is the answer to 3^{x+1}=15 ?
The answer to 3^{x+1}=15 is x=(ln(15))/(ln(3))-1
Solve for x: 3^{x+1}=15
The solution is x=(ln(15))/(ln(3))-1