What is the answer to 3^{1-7x}=81^{x-2}*9^{2x} ?

The answer to 3^{1-7x}=81^{x-2}*9^{2x} is x= 3/5

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3^{1-7x}=81^{x-2}*9^{2x}

3^{1 - 7 x} = 8 1^{x - 2} \cdot 9^{2 x}

x = \frac{3}{5}

Decimal Notation

x = 0.6

Solution steps

3^{1 - 7 x} = 8 1^{x - 2} \cdot 9^{2 x}

Apply exponent rules

1 - 7 x = 4 (x - 2) + 4 x

Solve

1 - 7 x = 4 (x - 2) + 4 x : x = \frac{3}{5}

x = \frac{3}{5}

(\frac{1}{4})^{9 x - 5} = 3 2^{x + 8}

2 5^{3 x - 1} = 5

9^{x + 2} = (\frac{1}{27})^{x - 3}

2^{x} = 1.5

4^{x} - 2^{x} - 12 = 0

What is the answer to 3^{1-7x}=81^{x-2}*9^{2x} ?
The answer to 3^{1-7x}=81^{x-2}*9^{2x} is x= 3/5
Solve for x: 3^{1-7x}=81^{x-2}*9^{2x}
The solution is x= 3/5