What is the answer to 9^{x+2}=(1/27)^{x-3} ?

The answer to 9^{x+2}=(1/27)^{x-3} is x=1

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9^{x+2}=(1/27)^{x-3}

9^{x + 2} = (\frac{1}{27})^{x - 3}

x = 1

Solution steps

9^{x + 2} = (\frac{1}{27})^{x - 3}

Apply exponent rules

2 (x + 2) = - 3 (x - 3)

Solve

2 (x + 2) = - 3 (x - 3) : x = 1

x = 1

2^{x} = 1.5

4^{x} - 2^{x} - 12 = 0

2 7^{5 x - 4} = 8 1^{7 x - 2}

5^{x - 1} = 2 + \frac{3}{5 ^{x - 2}}

What is the answer to 9^{x+2}=(1/27)^{x-3} ?
The answer to 9^{x+2}=(1/27)^{x-3} is x=1
Solve for x: 9^{x+2}=(1/27)^{x-3}
The solution is x=1