What is the answer to 3^{2x}=5^{x-1} ?

The answer to 3^{2x}=5^{x-1} is x=-(ln(5))/(2ln(3)-ln(5))

Solve for x: 3^{2x}=5^{x-1}

The solution is x=-(ln(5))/(2ln(3)-ln(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{2 x} = 5^{x - 1}

x = - \frac{ln ( 5 )}{2 ln ( 3 ) - ln ( 5 )}

Decimal Notation

x = - 2.73813 \dots

Solution steps

3^{2 x} = 5^{x - 1}

Apply exponent rules

2 x ln (3) = (x - 1) ln (5)

Solve

2 x ln (3) = (x - 1) ln (5) : x = - \frac{ln ( 5 )}{2 ln ( 3 ) - ln ( 5 )}

x = - \frac{ln ( 5 )}{2 ln ( 3 ) - ln ( 5 )}

e^{\frac{1}{x}} = 0

x^{x^{9}} = 3^{3}

- e^{- x} = 0

3 2^{\frac{x}{3}} = 8^{x - 12}

3^{x - 2} = 5^{x + 1}

What is the answer to 3^{2x}=5^{x-1} ?
The answer to 3^{2x}=5^{x-1} is x=-(ln(5))/(2ln(3)-ln(5))
Solve for x: 3^{2x}=5^{x-1}
The solution is x=-(ln(5))/(2ln(3)-ln(5))