What is the answer to 2^{3x+4}=18 ?

The answer to 2^{3x+4}=18 is x=(ln(9/8))/(3ln(2))

Solve for x: 2^{3x+4}=18

The solution is x=(ln(9/8))/(3ln(2))

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2^{3 x + 4} = 18

x = \frac{ln ( \frac{9}{8} )}{3 ln ( 2 )}

Decimal Notation

x = 0.05664 \dots

Solution steps

2^{3 x + 4} = 18

Apply exponent rules

(3 x + 4) ln (2) = ln (18)

Solve

(3 x + 4) ln (2) = ln (18) : x = \frac{ln ( \frac{9}{8} )}{3 ln ( 2 )}

x = \frac{ln ( \frac{9}{8} )}{3 ln ( 2 )}

4^{x^{2} - 6} - 1 6^{x + 1} = 0

x, e^{9 x} - 5 e^{3 x} + 4 = 0

2^{2 x + 1} - 9 \cdot 2^{x} + 4 = 0

4^{2 x - 5} = 64

e^{2 x} - 5 e^{x} - 6 = 0

What is the answer to 2^{3x+4}=18 ?
The answer to 2^{3x+4}=18 is x=(ln(9/8))/(3ln(2))
Solve for x: 2^{3x+4}=18
The solution is x=(ln(9/8))/(3ln(2))